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## Solved Examples

**Question 1:**Find the total cost of ten shirts at 30 dollar each and five pents at 70 dollars each.

**Solution:**

Cost of each shirt = 30

Number of shirts = 10

=> Cost of ten shirts = 30 * 10

=> Cost of ten shirts = 300

Again

Cost of each Pent = 70

Number of Pents = 5

=> Cost of five Pents = 70 * 5

=> Cost of five Pents = 350

Now

Total cost = Cost of ten shirts + Cost of five Pents

= 300 + 350

= 650

Hence, the total cost of ten shirts and five Pents is 650 dollars.

Number of shirts = 10

=> Cost of ten shirts = 30 * 10

=> Cost of ten shirts = 300

Again

Cost of each Pent = 70

Number of Pents = 5

=> Cost of five Pents = 70 * 5

=> Cost of five Pents = 350

Now

Total cost = Cost of ten shirts + Cost of five Pents

= 300 + 350

= 650

Hence, the total cost of ten shirts and five Pents is 650 dollars.

**Question 2:**The perimeter of a rectangle with breadth 10 m is 50 m. Find the length of the rectangle.

**Solution:**

Breadth of a rectangle = 10

Area of rectangle = 50

We know,

Area of rectangle = Length * Breadth

=> 50 = Length * 10

=> Length = $\frac{50}{10}$

= 5

=> Length of a rectangle is 5 m.

Area of rectangle = 50

We know,

Area of rectangle = Length * Breadth

=> 50 = Length * 10

=> Length = $\frac{50}{10}$

= 5

=> Length of a rectangle is 5 m.

**Question 3:**Find the sum of $\frac{3}{4}$ and $\frac{7}{-4}$.

**Solution:**

Given rational numbers = $\frac{3}{4}$ and $\frac{7}{-4}$

Step 1:

Make the denominator same

=> $\frac{7}{-4}$ = $\frac{7 * -1}{-4 * -1}$ = $\frac{-7}{4}$

Step 2:

Add both the fractions

=> $\frac{3}{4}$ + $\frac{-7}{4}$ = $\frac{3 + (-7)}{4}$

= $\frac{3 - 7}{4}$

= $\frac{-4}{4}$

= -1

=> $\frac{3}{4}$ + $\frac{7}{-4}$ = -1

Step 1:

Make the denominator same

=> $\frac{7}{-4}$ = $\frac{7 * -1}{-4 * -1}$ = $\frac{-7}{4}$

Step 2:

Add both the fractions

=> $\frac{3}{4}$ + $\frac{-7}{4}$ = $\frac{3 + (-7)}{4}$

= $\frac{3 - 7}{4}$

= $\frac{-4}{4}$

= -1

=> $\frac{3}{4}$ + $\frac{7}{-4}$ = -1